formed on a screen 20 cm from the slit. If the distance between successive minim

Question

formed on a screen 20 cm from the slit. If the distance between successive minima of the diffraction pattern is 2.1cm, what is the energy of the incident electrons? A neutron beam with a selected speed of 0.40 m/s is directed through a double slit with a 1.0-mm separation. An array of detector is placed 10 m from the slit. What is the de Broglie wavelength of the neutrons?. How far off axis is the first zero-intensity point on the detector array? (c) Can we say which slit any particular neutron passed through? Explain. A two-slit electron diffraction experiment is done with slits of unequal widths. When only slit 1 is open, the number of electrons reaching the screen per second is 25 times the number of electrons reaching die screen per second when only slit 2 is open. When both slits are

Explanation / Answer

? = h/px = h / mv = 6.625*10^-34 J.s / (1.67*10^-27)(0.4) = 9.92*10^-7 m or 992 nm
(b) The condition for dark fringe dsin? = (m + 1/2) ? here ? is very small so sin? = tan? = y/L and m = 1 (first order) (1*10^-3m)(y/L) = ( 1+1/2) (9.92*10^-7) (1*10^-3)y / ( 10) = 3/2 ( 9.92*10^-7)
therefore y = 30/2 (9.92*10^-4) = 0.0148 m
(c) According to uncertanity principle
we cannot find the position

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