What was the car\'s acceleration while stopping? How much work was done by frict

Question

What was the car's acceleration while stopping? How much work was done by friction to stop the car? What is the coefficient of kinetic friction between tires and road? What was the car's acceleration while stopping? How much work was done by friction to stop the car? What is the coefficient of kinetic friction between tires and road? How much work was done by friction to stop the car? How much work was done by friction to stop the car? What is the coefficient of kinetic friction between tires and road?

Explanation / Answer

(a) V^2 - U^2 = 2 a S ==> 0 - 21^2 = 2 a * 62 ==> a = - 3.556 m/s^2 (b) Work done by frictional force = change in KE = 0.5 * m U^2 = 0.5 * 1320 * 21^2 = 291060 J (c) The coefficient of friction uk = W / m g d = 291060 / 1320 * 9.8 * 62 = 0.362

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