What volume of oxygen will react with 21 mL of ethanol, assuming the gases are p

Question

What volume of oxygen will react with 21 mL of ethanol, assuming the gases are present at the same temperature and pressure? 2 CH_3CH_2OH(g) + 6 O_2(g) rightarrow 4 CO_2(g) + 6 H_2O(g) a. 7.0 mL b. 14 mL c. 21 mL d 42 mL e. 63 mL. If 0.357 g of CH_2 gas is introduced into an evacuated 1.75 L flask at 25 degree C. what is the pressure inside the flask? (R = 0.08206 L-atm/mol-K) a. 0.952 atm b. 0.261 atm c. 0.311 atm d. 0.419 atm e. 4.99 atm Carbon monoxide reacts with oxygen to form carbon dioxide. 2CO(g) + O_2(g) rightarrow 2 CO_2(g) In a 1.00 L flask, 4.30 atm of CO reacts with 2.50 atm of O_2. Assuming that the temperature remains constant, what is the final pressure in the flask? a. 1.80 atm b. 2.50 atm c. 4.30 atm d. 4.65 atm e. 6.80 atm

Explanation / Answer

11) volume of ethanol = 21 ml

For gases volume precentage equal to mole percentage.

Required oxygen = 3 x 21 = 63 ml

12) Mole of CH4 = 0.357/16 = 2.23 x 10-2 grams

PV = nRT

P = nRT/V

P = 2.23 x 10-2 x 0.08206 x 298/1.75 = 0.311 option (C) is correct.

13) 2CO +O2 = 2CO2

mole ratio is equal to pressure ratio

2CO + O2 = 2CO2

4.30 2.5 0 atm

-2.5 -2.5 2x2.5 atm

1.8 0 2x 2.5 = 5 atm

total pressure = 6.8 atm

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