6. A force table is set up with 2 pulleys at 50° and at 170° as shown at right.

Question

6. A force table is set up with 2 pulleys at 50° and at 170° as shown at right. A total of 200 grams is suspended from the pulley at 50° and a total of 300 grams is suspended from the pulley at 170°. A third string tied to the ring is attached to a force probe, and the probe is pulled so that the ring is in equilibrium in he center of the force table.
i. Find the magnitude of the tension force that the two strings shown exert on the ring. (You may use .) g˜10m/s2
ii. Use a ruler and a protractor to find the magnitude and direction of the tension force on the ring due to this third string. Be sure to indicate what scale you used.

Explanation / Answer

mx = 200 cos 50 -300 cos 10 = -167 gr (g cancels) my = 200 sin 50 + 300 sin 10 = 205 g The offsetting mass will be Mx = 167 gr and My = -205 g tan theta = -205 / 167 theta = -51 deg (below + x-axis) M = (167^2 + 205^2)^1/2 = 264 g F = M g = .264 * 9.8 = 2.59 N You should draw this on graph paper and verify

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