A circuit is constructed with five resistors and a battery as shown. The values

Question

A circuit is constructed with five resistors and a battery as shown. The values for the resistors are: R1 = R5 = 61 O, R2 = 152 O, R3 = 111 O, and R4 = 131 O. The battery voltage is V = 12 V. A circuit is constructed with five resistors and a battery as shown. The values for the resistors are: R1 = R5 = 61 O, R2 = 152 O, R3 = 111 O, and R4 = 131 O. The battery voltage is V = 12 V. What is I2, the current that flows through resistor R2? What is I1, the current that flows through the resistor R1? What is V4, the voltage across resistor R4? What is I2, the current that flows through resistor R2? What is I1, the current that flows through the resistor R1? What is I1, the current that flows through the resistor R1? What is V4, the voltage across resistor R4? What is V4, the voltage across resistor R4?

Explanation / Answer

First we get net resistance and then net current... R2,3 are series with 1 and 5, R4 is parallel with 2 and 3 so: R(2,3)= 152+111
=263 ohms 1/R(2,3,4)=(1/263+1/131) R(2,3,4)=87.44 R(1,2,3,4,5)=87.44+61+61    =209.44 ohms V=iR
i=12/209.44 =0.057A
This current will flow through each series element. Therefore,i1=0.057A for i2, current is divided between R(2,3) and R4 in the ratio of their resistances.
so i4/i(2,3)=R(2,3)/R4 (V1i1=V2i2)
i4/i(2,3)=263/131 =2 Therefore, 2i(2,3)=i(4) and i(2,3)+i(4)=0.057A so i(2)=i(3)=0.019A Finally, V4 is constant in parallel, so V4=V(2,3,4) V4=0.057*87.44    =4.98V

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