A car travels along a straight line at a constant speed of 60.0 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 60.0 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 30.0 mi/h. (a) what is the constant speed with which the car moved during the second distance d? (b) Suppose the second distance d were traveled in the opposite direction; you fotgot something and had to return home at the same constant speed as found in part (a). what is the average velocity for this trip? (c) what is the average speed for this new trip

Explanation / Answer

a)let the first speed for distance d is v1=60mi/h for the next d distance another speed =v2 then the average speed =(2*v1*v2)/(v1+v2) =30mi/h ?2*60*v2=30(60+v2) 120v2=1800+30v2 90v2=1800 v2=20mi/h b) for the new trip average velocity is zero. when u returned to the same point the net displacement is zero so average velocity is zero. c)the average speed is 30mi/h only because speed is irrespective of direction, can be caluculated from total distance and total time.

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