A mass with a charge of 4x10^-8 C and weighing 5 g falls toward earth. If the ma

Question

A mass with a charge of 4x10^-8 C and weighing 5 g falls toward earth. If the mag. of the electric field on the surface is 100 N/C, how much will the acceleration due to gravity change?
I have the answer below, but would like some help with the steps leading up to the answer. Im a little confused. Thank You!

(a-g) = Eq/m = 0.8x10^-3 m/s^2 A mass with a charge of 4x10^-8 C and weighing 5 g falls toward earth. If the mag. of the electric field on the surface is 100 N/C, how much will the acceleration due to gravity change?
I have the answer below, but would like some help with the steps leading up to the answer. Im a little confused. Thank You! (a-g) = Eq/m = 0.8x10^-3 m/s^2

Explanation / Answer

The force acting on the charge in electric field is F = Eq ......1 The force experience by the falling mass is F = ma .......2 ==> From 1 and 2 we have E q = m a ==> a = E q / m = 100 * 4 x 10^-8 / 5 x 10^-3 = 0.8 x 10^-3 m/s^2

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