A car slows down from a speed of 29.5 m/s to a speed of 14.0 m/s over a distance

Question

A car slows down from a speed of 29.5 m/s to a speed of 14.0 m/s over a distance of 415. m. (a) How long does this take, assuming constant acceleration?
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(b) What is the value of this acceleration? (Take the direction the car is going to be the positive direction. Indicate the direction with the sign of your answer.)
______________ thank you

A car slows down from a speed of 29.5 m/s to a speed of 14.0 m/s over a distance of 415. m. (a) How long does this take, assuming constant acceleration?
_____________

(b) What is the value of this acceleration? (Take the direction the car is going to be the positive direction. Indicate the direction with the sign of your answer.)
______________ thank you
(a) How long does this take, assuming constant acceleration?
_____________

(b) What is the value of this acceleration? (Take the direction the car is going to be the positive direction. Indicate the direction with the sign of your answer.)
______________ thank you

Explanation / Answer

(a) We have, s=(Vf+Vi)t/2 Hence, Time, t = 2s/ (Vf+Vi) = (2 * 415) / ( 14 + 29.5 ) = 19.1 s (b) Acceleration, a = (Vf^2 - Vi^2)/2s = (14^2-29.5^2) / ( 2 * 415 ) = - 0.812 m/s^2

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