A car slows down from a speed of 27.0 m/s to a speed of 14.0 m/s over a distance

Question

A car slows down from a speed of 27.0 m/s to a speed of 14.0 m/s over a distance of 370 m. (A) how long does this take, assuming constant acceleration? (B) what is the value of this acceleration? (Take the direction of the car is going to be the positive direction. Indicate the direction with the sign of your answer.) A car slows down from a speed of 27.0 m/s to a speed of 14.0 m/s over a distance of 370 m. (A) how long does this take, assuming constant acceleration? (B) what is the value of this acceleration? (Take the direction of the car is going to be the positive direction. Indicate the direction with the sign of your answer.) (A) how long does this take, assuming constant acceleration? (B) what is the value of this acceleration? (Take the direction of the car is going to be the positive direction. Indicate the direction with the sign of your answer.)

Explanation / Answer

A)

Vi = initial speed = 27 m/s

Vf = final velocity = 14 m/s

d = distance travelled = 370 m

a = acceleration

using the equation

Vf2 = Vi2 + 2 a d

(14)2 = (27)2 + 2 a (370)

a = - 0.72 m/s2

t = time taken

using the equation

Vf = Vi + a t

14 = 27 + (- 0.72) t

t = 18.1 sec

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