What is the acceleartion of the block with a mass of M=10kg that is being acted

Question

What is the acceleartion of the block with a mass of M=10kg that is being acted upon by applied force directed at 30 degrees above the horizontal? The block slides on a surface with µk =0.20 and achieves a velocity of v=4m/s after sliding d=2m.
What is the acceleartion of the block with a mass of M=10kg that is being acted upon by applied force directed at 30 degrees above the horizontal? The block slides on a surface with µk =0.20 and achieves a velocity of v=4m/s after sliding d=2m.

Explanation / Answer

We know that F.d = 0.5 M v^2 ==> F = 0.5 * 10 * 4*4 / 2 = 40 N The equation of motion is F cos30 - uk N = M a ==> Fcos30 - uk Mg = M a ==> a = [ F cos30 - uk Mg ] / M = [ 40 * cos30 - 0.20 * 10 * 9.8 ] / 10 = [ 34.64 - 19.6] / 10 = 1.504 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.