An iron disk has a radius of 0.645 m and a mass of 317 kg. Thedisk is mounted on

Question

An iron disk has a radius of 0.645 m and a mass of 317 kg. Thedisk is mounted on its axis so that it is free to spin. What torqueis required to give it an angular acceleration = 1.00rad/s2? If the torque is applied at the edge of the disk, how muchforce is required? How much force is required if the force is applied at adistance 17.5 cm from the axis of rotation? An iron disk has a radius of 0.645 m and a mass of 317 kg. Thedisk is mounted on its axis so that it is free to spin. What torqueis required to give it an angular acceleration = 1.00rad/s2? If the torque is applied at the edge of the disk, how muchforce is required? How much force is required if the force is applied at adistance 17.5 cm from the axis of rotation?

Explanation / Answer

The torque required to give it an angular acceleration of = 1.00 rad/s2 is = I * where I = (1/2)mr2,m = 317 kg and r = 0.645 m Let the required force be F therefore we get = I * = (1/4)mr2 * or F * r = (1/4)mr2 * or F = (1/4)mr * When the force is applied at a distance r = 17.5 cm = 17.5 *10-2 m,then the required torque is 1 = F * r

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