1. a disc of radius 40 cm and mass 5 kg free to rotate aboutan axis passing thro
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Question
1. a disc of radius 40 cm and mass 5 kg free to rotate aboutan axis passing through its center. A tangential force of 10 N isapplied on the disc. What is the angular acceleration of thedisc?2. a disc of radius 40 cm and mass 5 kg free to rotateabout an axis passing through its center. A tangential force of 10N is applied on the disc. What is the angular velocity of the discafter 10 s?
2. a disc of radius 40 cm and mass 5 kg free to rotateabout an axis passing through its center. A tangential force of 10N is applied on the disc. What is the angular velocity of the discafter 10 s?
Explanation / Answer
radius r = 40 cm = 0.4 m mass m = 5 kg Moment of inertia of the disc I = ( 1/ 2) m r ^ 2 = 0.4 kg m^ 2 force F = 10 N torque T = Fr = 4 Nm also we know T = I from this angular accleration = T / I = 10 rad / s^ 2 (2). time t= 10 s angular velocity after 10 s is w ' = w + t where w = initial angular speed = 0 plug the values we get w ' = 100 rad / sRelated Questions
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