An 8.0- kg mass rests on an inclined frictionlesssurface as shown in the figure
ID: 1681748 • Letter: A
Question
An 8.0- kg mass rests on an inclined frictionlesssurface as shown in the figure (except that the angle is63 o. A light string runs parallel to the surfacefrom the mass over a light, frictionless pulley to a 3.6- kgmass.
Find the acceleration of the masses. (Take downthe incline plane to be positive acceleration)
and Find the tension in thestring.
Explanation / Answer
The equation of motion for 8 kg block m1gsin - T = m1 a For 3.6 kg block T - m2g = m2 a Solving above two equations we have m1 g sin - m2g -m2a = m1 a ==> a = [ m1 g sin - m2g ] / [ m1 + m2] = [ 8 * 9.8 sin63 - 3.6 * 9.8 ] / [ 8 + 3.6 ] = 2.98 m/s2 The tension in the string is T - 3.6 * 9.8 = 3.6 * 7.857 ==> T = 38.29 N
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