3.) A rifle of 3.0 kg is fired. The velocity of a 10-gbullet at the muzzle is 30

Question

3.) A rifle of 3.0 kg is fired. The velocity of a 10-gbullet at the muzzle is 300 m/s. It takes 0.005 s for the bullet toreach the muzzle. Find a) the average force acting on the bullet;b) the recoil velocity of the rifle.
4.) A 1500-kg car at rest at a stop sign is hit frombehind by a 2500-kg truck at a speed of 10 m/s. They are entangledand skid together for a distance of 4.8 m. Find a) their speedright after the collision; b) the acceleration during the skid.
5.) A 3200-kg satellite revolves in a uniform circularmotion around the Earth at a height of 500 km. Find a) thegravitational force due to the Earth; b) the speed of thesatellite.(The mass of the Earth is 5.98 x 1024 kg andthe radius of the Earth is 6370 km.) 3.) A rifle of 3.0 kg is fired. The velocity of a 10-gbullet at the muzzle is 300 m/s. It takes 0.005 s for the bullet toreach the muzzle. Find a) the average force acting on the bullet;b) the recoil velocity of the rifle.
4.) A 1500-kg car at rest at a stop sign is hit frombehind by a 2500-kg truck at a speed of 10 m/s. They are entangledand skid together for a distance of 4.8 m. Find a) their speedright after the collision; b) the acceleration during the skid.
5.) A 3200-kg satellite revolves in a uniform circularmotion around the Earth at a height of 500 km. Find a) thegravitational force due to the Earth; b) the speed of thesatellite.(The mass of the Earth is 5.98 x 1024 kg andthe radius of the Earth is 6370 km.) 4.) A 1500-kg car at rest at a stop sign is hit frombehind by a 2500-kg truck at a speed of 10 m/s. They are entangledand skid together for a distance of 4.8 m. Find a) their speedright after the collision; b) the acceleration during the skid.
5.) A 3200-kg satellite revolves in a uniform circularmotion around the Earth at a height of 500 km. Find a) thegravitational force due to the Earth; b) the speed of thesatellite.(The mass of the Earth is 5.98 x 1024 kg andthe radius of the Earth is 6370 km.) 5.) A 3200-kg satellite revolves in a uniform circularmotion around the Earth at a height of 500 km. Find a) thegravitational force due to the Earth; b) the speed of thesatellite.(The mass of the Earth is 5.98 x 1024 kg andthe radius of the Earth is 6370 km.)

Explanation / Answer

3)a)mv=ft
0.01kg(300m/s)/0.005s=f

F=600N

b)conservation of momentum  3Kg(vgun)-0.01kg(300m/s)=0

Vgun= -1m/s <----negative because its goign the otherway.
4) a) conservation of momentum.

0(1500)+10m/s(2500kg)=4000kg(vfinal)

vfinal=6.25m/s

b) dx=4.8m
vinitial=6.25m/s

0^2=6.25m/s^2+2a(4.8m)

acceleration= -4.069m/s/s

6378.1km=radius of earth

altitude=500km

6878100m=r
G=6.67428*10^-11
M=5.9742*10^24kg

g=GMm/r^2
plug and chug

a) mg=27247.9N

b)Set this equation equal to its centripetal force to find itsvelocity.

27247.9N=mv^2/r

v^2=6878100(27247.9N)/3200kg

v=7652.895m/s <--final answer

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