3. th5ptial) Akallisti lep lulut le 175mssof2kgca hesap ectile of ass15g Thele g

Question

3. th5ptial) Akallisti lep lulut le 175mssof2kgca hesap ectile of ass15g Thele gehofthependula nis 30c nand (a) (4 points) Using the conservation of momentum, what is the velocity of the pendulum juat after abworbing the projectile? () (points) Using the conservation of energy, what is the potential energy of the pendulum and projectile system when it reaches its highest point? () (4 points) What height does this potential energy correspond to? (d) (3 points) What angle does the pendulum make at this height? point) A pole yaulter holds a long 11.1 m rod from one end. Their right hand is at the end of the rod and their left hand ia 0.78 m away from their right hand. The rod has a mass of 17.5 ks and the center of gravity is directly in the middle of the rod. (a) (3 points) Which point of the rod acts as the pivot point? 4. (15 points 0 ID b) (4 points) What torque does the force of gravity apply to the rod about the pivot point? 60 to the other side of the pivot point for the system to remain in static (c) (4 points) How much force must the pole vaulter apply equilibrium? 1568 . (d) (4 points) How much force must the pole vaulter apply at the pivot point for the system to remain in static equilibrium? Page 4

Explanation / Answer

3)

a)

M = mass of pendulum = 2 kg

m = mass of projectile = 15 gm = 0.015 kg

v = velocity of projectile before collision = 175 m/s

V = final velocity of the combination after collision

using conservation of momentum

mv = (m + M) V

(0.015) (175) = (2 + 0.015) V

V = 1.3 m/s

b)

Potential energy gained = kinetic energy just after collision = (0.5) (m + M) v2 = (0.5) (2 + 0.015) (1.3)2 = 1.7 J

c)

PE = 1.7

(m + M) gh = 1.7

(2 + 0.015) (9.8) h = 1.7

h = 0.086 m

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