A thin, flexiblerod of length L = 10 cm carries charge Q = 91 nC uniformly along

Question

A thin, flexiblerod of length L = 10 cm carries chargeQ = 91 nC uniformly along its length.The rod is then bent into a semicircle. What is the magnitude ofthe electric field at the center?       A.   4.0× 10^5 N/C
       B.   4.3 × 10^5 N/C
       C.   4.6 × 10^5 N/C
       D.   4.9 × 10^5 N/C
       E.    5.1 × 10^5 N/C
A thin, flexiblerod of length L = 10 cm carries chargeQ = 91 nC uniformly along its length.The rod is then bent into a semicircle. What is the magnitude ofthe electric field at the center?       A.   4.0× 10^5 N/C
       B.   4.3 × 10^5 N/C
       C.   4.6 × 10^5 N/C
       D.   4.9 × 10^5 N/C
       E.    5.1 × 10^5 N/C
      A.   4.0× 10^5 N/C
       B.   4.3 × 10^5 N/C
       C.   4.6 × 10^5 N/C
       D.   4.9 × 10^5 N/C
       E.    5.1 × 10^5 N/C

Explanation / Answer

The radius of the semi circle is r = L / = 0.1/ 3.14 = 0.0318 m Charge Q = 91 x 10-9 C The electric field at the center is                                      E = 2 k Q / r2                                         = 2 * 9 x 109 * 91 x 10-9 / 3.14 *(0.0318)2                                         = 5.142 x 105 N/C So option E is correct answer.

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