A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed

Question

A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed so that the normal to its plane makes an angleof 50.9° with a uniform magnetic field of magnitude 15.0 T.(a) Calculate the magnitude of the magnetic dipolemoment of the loop in amperes-square meters. (b)What is the magnitude of the torque acting on the loop?
Thanks for the help! A circular wire loop of radius 14.9 cm carries a current of3.04 A. It is placed so that the normal to its plane makes an angleof 50.9° with a uniform magnetic field of magnitude 15.0 T.(a) Calculate the magnitude of the magnetic dipolemoment of the loop in amperes-square meters. (b)What is the magnitude of the torque acting on the loop?
Thanks for the help!

Explanation / Answer

Given that Radius of the loop is(r) =14.9 cm                                    =0.149m Current in the loop(i) = 3.04 A Magnitude of magnetic field(B) =15.0 T Angle() =50.90
Number of turns (N) = 1 Area (A) = r2              =3.14*0.1492             = 0.06971m2 a) Magnitude of magnetic field is               = NiA                  =(1)(3.04)(0.06971)                  =0.21192 A.m2 b) Magnitude of torque acting on the loopis                = x B                   = BSin                   =(0.21192)(15)Sin 50.90                   = 2.4669N.m b) Magnitude of torque acting on the loopis                = x B                   = BSin                   =(0.21192)(15)Sin 50.90                   = 2.4669N.m

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