(a) Find the electric flux through surface1. 1__________N · m 2 /C (b) Find the

Question

(a) Find the electric flux through surface1.
1__________N · m2/C

(b) Find the electric flux through surface 2.
2__________N · m2/C The drawing shows an edge-on view of two planar surfaces thatintersect and are mutually perpendicular. Surface 1 has an area of1.6 m^2, while surface 2 hasan area of 3.0 m^2. The electric field vector E in the drawing is uniform and has a magnitude of 275 N/C. (a) Find the electric flux through surface1. 1__________N m^2/C (b) Find the electric flux through surface 2. 2__________N m^2/C

Explanation / Answer

                                                  = EA cos where = angle between E and normal of the area (A) For surface 1   = 35 o So , flux = 275 N / C * 1.6 m 2 * cos 35 o               = 360.42 N - m 2 / C Electric flux through surface 2 is = E . A                                                   = EA cos where = angle between E and normal of the area (A) For surface 2    =  90 - 35 =55 o So , flux = 275 N / C * 3.0 m 2 * cos 55 o               = 473.20 N - m 2 / C
So , flux = 275 N / C * 1.6 m 2 * cos 35 o               = 360.42 N - m 2 / C Electric flux through surface 2 is = E . A                                                   = EA cos where = angle between E and normal of the area (A) For surface 2    =  90 - 35 =55 o So , flux = 275 N / C * 3.0 m 2 * cos 55 o               = 473.20 N - m 2 / C
                                                  = EA cos where = angle between E and normal of the area (A) For surface 2    =  90 - 35 =55 o So , flux = 275 N / C * 3.0 m 2 * cos 55 o               = 473.20 N - m 2 / C
So , flux = 275 N / C * 3.0 m 2 * cos 55 o               = 473.20 N - m 2 / C

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