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A simple pendulum, 2.0m in length, is released by a push whenthe support string

ID: 1680812 • Letter: A

Question

A simple pendulum, 2.0m in length, is released by a push whenthe support string is at an angle of 25 degrees from the vertical.If the initial speed of the suspended mass is 1.2m/s when at therelease point, to what maximum angle will it move in the secondhalf of its swing? (answers in degrees) a) 37 b) 30 c) 27 d) 21 e) none A simple pendulum, 2.0m in length, is released by a push whenthe support string is at an angle of 25 degrees from the vertical.If the initial speed of the suspended mass is 1.2m/s when at therelease point, to what maximum angle will it move in the secondhalf of its swing? (answers in degrees) a) 37 b) 30 c) 27 d) 21 e) none

Explanation / Answer

L = 2.0 m, = 25o, v = 1.2 m/s, find ' initial energy = mv2/2 + mgL(1 - cos) final energy = mgL(1 - cos') mv2/2 + mgL(1 - cos) = mgL(1 - cos') cos' = cos - v2/(2gL) ' = cos-1[cos - v2/(2gL)]= 30o answer: b

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