A simple pendulum is located on a planet that has the same mass and radius as Ea

Question

A simple pendulum is located on a planet that has the same mass and radius as Earth. If the length of the pendulum is 2.0 m, what will be the period of oscillation that the pendulum exhibits? What would be the acceleration due to gravity on a planet where the same simple pendulum had a period of oscillation that was four times as great as that on the first planet?
Extra Credit 10 points: If the pendulum is started from an angle of 10 degrees from the vertical, what is the equation of motion (position) of the pendulum on each of the two planets?

Explanation / Answer

g=9.8 m/s

T=2*pi*(l/g)^1/2

=2.838 s

b)4*2pi*(l/g)^0.5=2pi*(l/g')^0.5

or g'=g/16

=0.6125 m/s^2

c)ist planet, A=0.03cos(2.213*t)

2nd planet: A=0.03cos(0.553*t

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