1. The flywheel of a steam engine runs with a constantangular speed of 165 rev/m
ID: 1680725 • Letter: 1
Question
1. The flywheel of a steam engine runs with a constantangular speed of 165 rev/min. When steam is shut off, the friction of the bearings and ofthe air brings the wheel to rest in 2.30 h. (a) What is the constant angular acceleration of the wheel, inrev/min2 ? (b) How many rotations will the wheel make before coming torest? (c) What is the tangential linear acceleration of a point 54.2cm from the axis of rotation when the flywheel is turning at 75/2 rev/min (d) What is the magnitude of the total linear acceleration ofthe point in part (c)? 1. The flywheel of a steam engine runs with a constantangular speed of 165 rev/min. When steam is shut off, the friction of the bearings and ofthe air brings the wheel to rest in 2.30 h. (a) What is the constant angular acceleration of the wheel, inrev/min2 ? (b) How many rotations will the wheel make before coming torest? (c) What is the tangential linear acceleration of a point 54.2cm from the axis of rotation when the flywheel is turning at 75/2 rev/min (d) What is the magnitude of the total linear acceleration ofthe point in part (c)?Explanation / Answer
Given that the initial angular velocity is 1 =165 rev/min = 16.74 rad/s Final angular velocity is 2 = 0 rad/s Time taken is t = 2.3 h = 2.3*60*60 s = 8280 s ---------------------------------------------------------------------- The angular acceleration is = ( 2 - 1 ) /t = -------- rad/s2 Angular displacement is = (22 - 12 ) /2 =--------- rad convert angulardisplacement in to revolutions as one rev = 2 rad The linear velocity is v = 0.542m *(75 rev/min) *(2rad/rev)*(min / 60s) = __ m/s linear radial acceleration is ar = v2/ r = -------- m/s2 Tangential acceleration is at =r * = ---------- m/s2 Net acceleration is a = ( ar +at)1/2 = ----------- m/s2
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