An object is placed in front of a diverging lens with a focallength of 18.1 cm.

Question

An object is placed in front of a diverging lens with a focallength of 18.1 cm. For eachobject distance, find the image distance and the magnification.Describe each image.
(a) 36.2 cm location cm magnification nature real virtual upright inverted
(b) 18.1 cm location cm magnification nature real virtual upright inverted
(c) 9.05 cm location cm magnification nature real virtual upright inverted (a) 36.2 cm location cm magnification nature real virtual upright inverted
(b) 18.1 cm location cm magnification nature real virtual upright inverted
(c) 9.05 cm location cm magnification nature real virtual upright inverted location cm magnification nature real virtual upright inverted

Explanation / Answer

f=18.1 cm we know 1/f=1/d1+1/d2=>d2=1/(1/f-1/d1) a) d=36.2=>d2=1/(1/18.1-1/36.2)=36.2 M=-d2/d1=-1 image is real and upringt b)d1=18.1 =>d2= iimage is virtual c) d1=9.05 =>d2=1/(1/18.1-1/9.05)=-18.1 M=-d2/d1=2 image is virtual and inverted

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