An object is placed 40 cm from a lens. The image formed by the lens has a magnif

Question

An object is placed 40 cm from a lens. The image formed by the lens has a magnification of +4.

1. What is the image position

A. +160 cm

B. + -160

C. +10 cm

D. -10 cm

I am using m = - di/do....working out to -160 cm?

2. What is the focal length of the lens and what type of lens is it?

A. +53.3 cm, convergent

B. -53.3 cm, divergent

C. +32 cm, convergent

D. -32 cm, divergent

3. What type of image is the one formed by this lens?

A. real, inverted, and larger than the object

B. real, upright, and larger than the object

C. virtual, inverted and larger than the object

D. virtual, upright and larger than the object

Explanation / Answer

1)1/u+1/v=1/f

-(v)/u=4

v=-4u=-160cm

option B

B)1/40-1/160=1/f

f=160/3=+53.2 cm and converging

and image is virtual upright and larger than the original object

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