I apologize ahead of time for the diagram I scanned it in andcant figure out how
ID: 1678898 • Letter: I
Question
I apologize ahead of time for the diagram I scanned it in andcant figure out how to insert it into the question.... https://s3.amazonaws.com/answer-board-image/2010429161322634081544026880000472.jpgsuppose 67.5 moles of an ideal monatomic gas undergo the series ofprocesses shown in the figure.
I figured out A and B I just need help on C
(a) calculate the temperature at the points A, B, and C. A: 267 K, B: 357K, C= 89.1 K suppose 67.5 moles of an ideal monatomic gas undergo the series ofprocesses shown in the figure.
I figured out A and B I just need help on C (a) calculate the temperature at the points A, B, and C.
(b) for each process, A --> B, B --> C, and C --> A. statewhether heat enters or leaves the system. explain in eachcase. enters, exists, enters (b) for each process, A --> B, B --> C, and C --> A. statewhether heat enters or leaves the system. explain in eachcase.
(c) calculate the heat exchanged with the gas during each of thethree processes.
(c) calculate the heat exchanged with the gas during each of thethree processes.
Explanation / Answer
n = 67.5 moles, Cv = 3R/2, Cp = 5R/2 TA = 267 oC, TB = 357oC, TC = 89.1 oC (from (a)) c) QCA = nCv(TA - TC) =n*1.5R*(TA - TC) =1.5*(PAVA - PCVC) =1.50*105 J QBC = nCp(TC - TB) =n*2.5R*(TC - TB) =2.5*(PCVC - PBVB) =-3.75*105 J (negative means heat leaves from thesystem) QAB = WAB + UAB = (150 +50)*103*3/2 + n*1.5R*(TB - TA) = 3.00*105 + 1.5*(PBVB -PAVA) = 3.75*105 J
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