A thin film of soap with n = 1.39 hanging in the airreflects dominantly red ligh

Question

A thin film of soap with n = 1.39 hanging in the airreflects dominantly red light with = 651 nm. The minimumthickness of the filmis 1.171×102 nm
Now this film is ona sheet of glass, with n = 1.46. What is the wavelength of thelight in air that will now be predominantlyreflected?
HINT:
What changed compared to previous problem? What is therequirement for a maximum for the pathlength difference now?
Now this film is ona sheet of glass, with n = 1.46. What is the wavelength of thelight in air that will now be predominantlyreflected?
HINT:
What changed compared to previous problem? What is therequirement for a maximum for the pathlength difference now? What changed compared to previous problem? What is therequirement for a maximum for the pathlength difference now? What changed compared to previous problem? What is therequirement for a maximum for the pathlength difference now?

Explanation / Answer

given that n = 1.39 = 651nm minium thick ness of the film = t = /4n = 651nm/4 *1.39 = 1.171×102 nm if n = 1.46 then    = 4nt = 4 *1.46 * 1.171×102 nm= 683.2nm path difference difference depend on both n and t value if n value change inversily t valuechange

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