Why does step 3 inquestion 44 in ch 14 in the book College physics (8th) By Youn

Question

Why does step 3 inquestion 44 in ch 14 in the book College physics (8th) By Youngcompute (.5kg)(.39*10^3 J/kg.K)=.195 ??????
taking .39*10^3 out of scientific notation makes it 390.
so (390)(.5) =195 !!!! right??? I dont get it. someone explainit to me. will rate lifesaver Why does step 3 inquestion 44 in ch 14 in the book College physics (8th) By Youngcompute (.5kg)(.39*10^3 J/kg.K)=.195 ??????
taking .39*10^3 out of scientific notation makes it 390.
so (390)(.5) =195 !!!! right??? I dont get it. someone explainit to me. will rate lifesaver will rate lifesaver

Explanation / Answer

if there is nothing like that then that is nothing but amisprint in the book...

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