Electrons are accelerated from rest through a potentialdifference of V o and the
ID: 1677520 • Letter: E
Question
Electrons are accelerated from rest through a potentialdifference of Vo and then pass through aregion between two parallel metal plates. The region betweenplates contains a uniform electric field E and uniform magneticfield B. With only electric field present electrons followpath 1. With only magnetic field present electrons followpath 3 . With both fields present electrons pass undeflectedalong straight path 2 a) Describe shape of the portion of path 1 betweenplates Justify your answer b) what is direction of electric field Explain c) Describe shape of portion of path 3 between plates. Justify your answer d) Between plates the magnitude of electric field is 3.4 x 104 V/m and magnitude of magnetic field is 2.0 x 10-3 T Claculate speed ofelectrons given they are undeflected when both fields arepresent e) Calculate V o , potential difference,required to accelerate electrons to speed determined above Electrons are accelerated from rest through a potentialdifference of Vo and then pass through aregion between two parallel metal plates. The region betweenplates contains a uniform electric field E and uniform magneticfield B. With only electric field present electrons followpath 1. With only magnetic field present electrons followpath 3 . With both fields present electrons pass undeflectedalong straight path 2 a) Describe shape of the portion of path 1 betweenplates Justify your answer b) what is direction of electric field Explain c) Describe shape of portion of path 3 between plates. Justify your answer d) Between plates the magnitude of electric field is 3.4 x 104 V/m and magnitude of magnetic field is 2.0 x 10^-3 T Claculate speed ofelectrons given they are undeflected when both fields arepresent e) Calculate V o , potential difference,required to accelerate electrons to speed determined aboveExplanation / Answer
Potential difference V= Vo
Initial speed u = 0
(a). shape of the portion of path 1 between plates isparabolic
b) The direction of electric field is from top plate tobottom plate
c) The shape of portion of path 3 between plates is circular
d) the magnitude of electric field B = 3.4 x 104 V/m
magnitude of magnetic field B = 2.0 x 10-3 T
speed of electrons given they are undeflected when both fieldsare present is v = E / B
= 17*10^6 m / s
e) potential difference, required to accelerate electronsto speed determined above be V o
we know v = [ 2Voq / m]
where m = mass of electron = 9.11 * 10 ^ -31 kg
q = charge of electron = 1.6 * 10 ^ -19 C
from above equation Vo = ( 1/ 2q) mv^ 2
plug the values we get Vo = 822.74 Volt
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