A lifeguard is working at a pool sitting in his guardstand. He notices a child r

Question

A lifeguard is working at a pool sitting in his guardstand. He notices a child right below him drowning thatappears to be 1.5 m below the surface of the water? How deepis the child actually? Assume he is sees the child at a verysmall angle, and use the small angle approx. of sin= tan = A lifeguard is working at a pool sitting in his guardstand. He notices a child right below him drowning thatappears to be 1.5 m below the surface of the water? How deepis the child actually? Assume he is sees the child at a verysmall angle, and use the small angle approx. of sin= tan =

Explanation / Answer

it is known that real depth divided by apparent depth gives you therefractive index of the material(in this case, water): real depth/1.5=1.33 real depth=1.5*1.33              =1.995 m              approx 2m

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