A levitating train is three cars long and has a mass of 100 metric tons. The cur

Question

A levitating train is three cars long and has a mass of 100 metric tons. The current in the superconducting wires is about 500 kA, and even though the traditional design calls for many small coils of wire, assume for this problem that there is a 180 m long wire carrying the current. Find the size of the magnetic field needed to levitate the train. Please show your work

A levitating train is three cars long (180 m) and has a mass of 100 metric tons (1 metric ton = 1000 kg). The current in the superconducting wires is about 500 kA, and even though the traditional design calls for many small coils of wire, assume for this problem that there is a 180-m-long wire car-rying the current. Find the size of the magnetic field needed to levitate the train.

Explanation / Answer

let field be B.

then B*N*I*L=mass*g

B*1*180*500*10^3=1000*9.8

B=1.088*10^(-4)

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