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An object , which has a height of 14.0 cm, is placed 25.0 cmin front of a convex

ID: 1674865 • Letter: A

Question

An object , which has a height of 14.0 cm, is placed 25.0 cmin front of a convex mirror. Which has a focal length of -45.0 cm : a) What is the radius of curvature of this mirror? b) What will be the position of the resulting image? c) What will be the magnification of the resultingimage? d) What will be the height of the , resulting image? e) Is the resulting image real or virtual? Explain! f) What is the maximum magnification that this mirror iscapable of producing ? An object , which has a height of 14.0 cm, is placed 25.0 cmin front of a convex mirror. Which has a focal length of -45.0 cm : a) What is the radius of curvature of this mirror? b) What will be the position of the resulting image? c) What will be the magnification of the resultingimage? d) What will be the height of the , resulting image? e) Is the resulting image real or virtual? Explain! f) What is the maximum magnification that this mirror iscapable of producing ?

Explanation / Answer

height of the object   h o = 14 cm object distance   do   = 25cm focal length   f = 45 cm radius of the mirror R = 2f                                       = 2*45   = 90 cm equation of spherical mirror            1 / do + 1 / di = 1 /f                        1 / d i =   1 /f   - 1 / d o                                     =  1 / 45 -1/ 25   image distance distance   di     =   -56.24cm magnification of resulting image                      M = - di / do                          =  -( -56.24)   / 25                          = 2.24 height of the resulting image   hi   = M ho                                                   = 2.24*14                                                   = 31.49 cm resulting image is virtual .                                               
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