The allowed energies of a simple atom are 0.00eV , 4.31eV ,and 6.60eV . What wav

Question

The allowed energies of a simple atom are 0.00eV , 4.31eV ,and 6.60eV . What wavelengths appear in the atom'semission spectrum?
What wavelengths appear in the atom's absorption spectrum? f=Ephoton/h is how I get the frequency and then I use the cwhich is = to the speed of light to get c/f which gives me lamda ormy wavelength but every time I do that I get 188nm, 288nm and 0 butI those arent the right answers so Im lost as too what Im doingwrong or missing. What wavelengths appear in the atom'semission spectrum?
What wavelengths appear in the atom's absorption spectrum? f=Ephoton/h is how I get the frequency and then I use the cwhich is = to the speed of light to get c/f which gives me lamda ormy wavelength but every time I do that I get 188nm, 288nm and 0 butI those arent the right answers so Im lost as too what Im doingwrong or missing.

Explanation / Answer

You need to use the energy difference between the energy levels.So, from 0 to 4.31 we get 4.31 eV, from 0 to 6.6 we get 6.6 eV, andfrom 4.31 to 6.6 we get 2.29 eV. So, the two non-zero wavelengths you have should be correct since you happened to use the right energies,but for the last one, you need to use 2.29 eV as your energy. 2.29 / (4.136*10-15) = 5.537 * 10-14 3.0 * 108 / (5.537 * 10-14) = 5.42 *10-7m = 542 nm

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