Will rate lifesaver! Please explain each step indetail so that it\'s easy to und

Question

Will rate lifesaver! Please explain each step indetail so that it's easy to understand and replicate on a test!thank you for your help. A ball of mass 0.120 kg isdropped from rest from a height of 1.25 m. It rebounds from thefloor to reach a height of 0.600 m.What impulse was given to the ball by the floor?
----- kg·m/s Will rate lifesaver! Please explain each step indetail so that it's easy to understand and replicate on a test!thank you for your help. A ball of mass 0.120 kg isdropped from rest from a height of 1.25 m. It rebounds from thefloor to reach a height of 0.600 m.What impulse was given to the ball by the floor?
----- kg·m/s A ball of mass 0.120 kg isdropped from rest from a height of 1.25 m. It rebounds from thefloor to reach a height of 0.600 m.What impulse was given to the ball by the floor?
----- kg·m/s

Explanation / Answer

let the speed before hit the floor be v and rebound speed beu for energy conservation: (1/2)mv2 = mg*1.25m =>v = 2g*1.25m=(2*9.8m/s2*1.25m) =4.95m/s let up be positive, v = -4.95m/s also: (1/2)mu2 = mg*0.600m =>u = (2*9.8m/s2*0.600m) = 3.43 m/s impuse = P = mu - mv = 0.120kg*(3.43m/s - (-4.95m/s)) =1.0056 kg*m/s .

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