This is a question I have to solve from: University Physics with Modern Physics(

Question

This is a question I have to solve from: University Physics with Modern Physics(12th) by Young,Freedman Problem 78 I know the question is from this book however the solution oncramster is not the solution needed for the question askedwith number 78
A 4.92-g bullet is shotthrough a 0.95-kg wood blocksuspended on a string 2.00 m long. The center of mass of the blockrises a distance of 0.42 cm. Find thespeed of the bullet as it emerges from the block if its initialspeed is 402 m/s.
This is a question I have to solve from: University Physics with Modern Physics(12th) by Young,Freedman Problem 78 I know the question is from this book however the solution oncramster is not the solution needed for the question askedwith number 78
A 4.92-g bullet is shotthrough a 0.95-kg wood blocksuspended on a string 2.00 m long. The center of mass of the blockrises a distance of 0.42 cm. Find thespeed of the bullet as it emerges from the block if its initialspeed is 402 m/s.

Explanation / Answer

Mass of bullet m = 4.92 * 10 ^ -3 kg

Mass of wood M = 0.95 kg

Length L = 2m

Height h = 0.42 cm =0.42 * 10 ^ -2 m

Initia; speed of the bullet v = 402 m / s

We know speed of the wood just after collision V = [ 2gh]

                                                                               = 0.2869 m / s

From law of conservation of energy ,

Initial K.E of bullet = K.E of bullet just after collision + K.Eof wood just after collision

        ( 1/ 2) mv ^ 2 =( 1/ 2) mv ‘ ^ 2 + ( 1/ 2) M V ^ 2

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