Please show all formulas and steps....\'free body\'(diagrams) if possible .A per

Question

Please show all formulas and steps....'free body'(diagrams) if possible
.A person is pulling a 12.0 kg box across a smooth horizontalsurface. What is the acceleration of the box if they are pullingupward at an angle of 37 degrees with a force of 95.3Newtons? Please show all formulas and steps....'free body'(diagrams) if possible
.A person is pulling a 12.0 kg box across a smooth horizontalsurface. What is the acceleration of the box if they are pullingupward at an angle of 37 degrees with a force of 95.3Newtons?

Explanation / Answer

The equation of motion is            Fcos - mgsin = ma ==> a = [ F cos - mgsin ] / m            = [ 95.3 cos37 - 12 * 9.8 sin37 ] / 12            = 0.444 m/s2

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