R = 5.1, r = 1.2.) (a) the magnitude of the current and thedirection of positive
ID: 1670598 • Letter: R
Question
R = 5.1, r = 1.2.) (a) the magnitude of the current and thedirection of positive current(b) the potential difference across the battery terminals a andb
(c) the rate at which heat is being produced in the 5.1 resistor
(d) the rate at which heat is being produced inside the battery
(e) the rate at which the battery's chemical energy is beingused
For the circuit in the figure below, find the following. (Take E = 6.2 V, R = 5.1 Omega and r = 1.2 Omega . (a) the magnitude of the current and thedirection of positive current (b) the potential difference across the battery terminals a andb (c) the rate at which heat is being produced in the 5.1 Omega resistor (d) the rate at which heat is being produced inside the battery (e) the rate at which the battery's chemical energy is beingused
Explanation / Answer
(a) direction of positive current is clockwise around the loop. . Magnitude of current = total potential / totalresistance = 6.2 / (5.1 + 1.2) = 0.9841 A . (b) pot diff = IR = 0.9841 * 5.1 = 5.019 Volts . (c) rate of heat = I2 R =0.98412 * 5.1 = 4.939 Watts . (d) rate of hear = I2 r =0.98412 * 1.2 = 1.162 Watts . (e) rate of chemical energy use = E I = 6.2 * 0.9841 = 6.101 WattsRelated Questions
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