A block of mass, M=1 kg, is released from top of an incline.The block slides dow

Question

A block of mass, M=1 kg, is released from top of an incline.The block slides down the plane and attains a final speed of 6 m/sat the bottom. it then slides horizontally on a frictionlessurface, and collides and sticks to another block of mass, m=0.25kg, which is at rest. what is the coefficient of kinetic friction of theincline plaine? h=1.8 =30 A block of mass, M=1 kg, is released from top of an incline.The block slides down the plane and attains a final speed of 6 m/sat the bottom. it then slides horizontally on a frictionlessurface, and collides and sticks to another block of mass, m=0.25kg, which is at rest. what is the coefficient of kinetic friction of theincline plaine? h=1.8 =30

Explanation / Answer

We can write          mgsin - fk =ma ==> mgsin - kmgcos =ma     ....1 Where the acceleration of the block is         v2 = 2ah ==> a = v2 / 2h            = 36 / 2*1.8            = 10 m/s2 Substituting in 1 we get Therefore            k = tan = tan30 = 0.577

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