A generator is designed to produce a maximum emf of 180 Vwhile rotating with an

Question

A generator is designed to produce a maximum emf of 180 Vwhile rotating with an angular speed of 3300 rpm . Each coilof the generator has an area of1.9×102 m2. If the magnetic field used in the generatorhas a magnitude of 4.5×102 T , how many turns of wire are needed? A generator is designed to produce a maximum emf of 180 Vwhile rotating with an angular speed of 3300 rpm . Each coilof the generator has an area of1.9×102 m2. If the magnetic field used in the generatorhas a magnitude of 4.5×102 T , how many turns of wire are needed? If the magnetic field used in the generatorhas a magnitude of 4.5×102 T , how many turns of wire are needed?

Explanation / Answer

Maximum emf E = 180 V

Angular speed w = 3300 rpm

                           = 3300 * 2(pi) rad / 60 s

                           = 345.57 rad / s

Area   A= 1.9 * 10^-2 m ^ 2

Magnetic field B = 4.5 * 10 ^ -2 T

We know E = BANw

From this No.of truns N = E / ( BA w )

                                        = 609.2 ~ 610

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