Determine the magnetic field magnitude due to wire A at theposition of wire B. E
ID: 1669250 • Letter: D
Question
Determine the magnetic field magnitude due to wire A at theposition of wire B. Express your answer using two significant figures.Determine the magnetic field due to wire B at the position of wireA. Express your answer using two significant figures.
Determine the force on wire A due to wire B, and the force on wireB due to wire A. Express your answer using two significant figures. Determine the magnetic field magnitude due to wire A at theposition of wire B. Express your answer using two significant figures.
Determine the magnetic field due to wire B at the position of wireA. Express your answer using two significant figures.
Determine the force on wire A due to wire B, and the force on wireB due to wire A. Express your answer using two significant figures. Determine the magnetic field due to wire B at the position of wireA. Express your answer using two significant figures.
Determine the force on wire A due to wire B, and the force on wireB due to wire A. Express your answer using two significant figures. Determine the force on wire A due to wire B, and the force on wireB due to wire A. Express your answer using two significant figures.
Explanation / Answer
(a) B = k I / r = 2 x10-7 * 2.0 / 0.17 = 2.353 x10-6 Tesla . (b) B = k I / r = 2 x10-7 * 3.8 / 0.17 = 4.471 x10-6 Tesla . (c) the forces are the same and are equal to . force per unit length = currentof one wire * B field from the other = . = 3.8 * 2.353 x 10-6= 8.941 x10-6 newtons per meter . Or 2.0 * 4.471x 10-6 = 8.941 x10-6 newtons per meter . (c) the forces are the same and are equal to . force per unit length = currentof one wire * B field from the other = . = 3.8 * 2.353 x 10-6= 8.941 x10-6 newtons per meter . Or 2.0 * 4.471x 10-6 = 8.941 x10-6 newtons per meterRelated Questions
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