Q A tennis ball is thrown straight up from thesurface of the Earth with an initi

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Q A tennis ball is thrown straight up from thesurface of the Earth with an initial speed of 25.0 m/s. Neglectingany effect of air resistance .Answer the fowwing question (a)What is the magnitude of the ball displacement from thestarting point after 1.50 seconds have elapsed? y=vot+1/2at2 (b)For this initial velocity, how much time elapse between thethrowing of the ball and its return to the original launchpoint? - vot+1/2at2 (c)What maximum height will the ballreach? -vf2=vo2+2ay            this is a vector quantity           Q A tennis ball is thrown straight up from thesurface of the Earth with an initial speed of 25.0 m/s. Neglectingany effect of air resistance .Answer the fowwing question (a)What is the magnitude of the ball displacement from thestarting point after 1.50 seconds have elapsed? y=vot+1/2at2 (b)For this initial velocity, how much time elapse between thethrowing of the ball and its return to the original launchpoint? - vot+1/2at2 (c)What maximum height will the ballreach? -vf2=vo2+2ay            this is a vector quantity          

Explanation / Answer

a) let upward be positive the acceleration is a= -g = -9.8m/s2 y = v0t + (1/2)at2 = 25.0m/s*1.50s +(1/2)*(-9.8m/s2)*(1.50s)2 = 26.5m b) time in air t = 2v0 /g = 2*25.0m/s /9.8m/s2 = 5.10s c) max height H = v02 / 2g =(25m/s)2 / 2*9.8m/s2 = 31.9 m y = v0t + (1/2)at2 = 25.0m/s*1.50s +(1/2)*(-9.8m/s2)*(1.50s)2 = 26.5m b) time in air t = 2v0 /g = 2*25.0m/s /9.8m/s2 = 5.10s c) max height H = v02 / 2g =(25m/s)2 / 2*9.8m/s2 = 31.9 m

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