1) According to Newton\'s third law, each team in a tug of war(Fig. 4-31) pulls

Question

1) According to Newton's third law, each team in a tug of war(Fig. 4-31) pulls with equal force on the other team. Suppose thateach team pulls with a force of 6,705 N, but that neither moves atall. What is the tension (in N) in the rope? ( Answer: 6.71 ×103) 2) A roller coaster makes a vertical circle(loop-the-loop) with a radius of curvature of 5.2 m. At whatminimum speed (in m/s) must a roller coaster car be traveling whenupside down at the top of a circle so that the passengers are notto fall out if they are not strapped in? ( Answer: 7.14 ×100) 3) In an experiment on stopping distance, a truck drives 60mph, then the brakes are put on hard, so that the truck's wheelslock, and the truck skids to a stop. When the truck is empty, ithas a mass of 3000 kg, and it skids to a stop in 30 m. Whatdistance (in m) does the truck skid when it is loaded with a2,507-kg mass? ( Answer: 3.00 × 101) 1) According to Newton's third law, each team in a tug of war(Fig. 4-31) pulls with equal force on the other team. Suppose thateach team pulls with a force of 6,705 N, but that neither moves atall. What is the tension (in N) in the rope? ( Answer: 6.71 ×103) 2) A roller coaster makes a vertical circle(loop-the-loop) with a radius of curvature of 5.2 m. At whatminimum speed (in m/s) must a roller coaster car be traveling whenupside down at the top of a circle so that the passengers are notto fall out if they are not strapped in? ( Answer: 7.14 ×100) 3) In an experiment on stopping distance, a truck drives 60mph, then the brakes are put on hard, so that the truck's wheelslock, and the truck skids to a stop. When the truck is empty, ithas a mass of 3000 kg, and it skids to a stop in 30 m. Whatdistance (in m) does the truck skid when it is loaded with a2,507-kg mass? ( Answer: 3.00 × 101)

Explanation / Answer

So according to Newton'law. net force act on both team arezero. so T=F1=F2=6,71e3(N). 2). For the passenger to not being fall out. the centripetal acceleration is larger than the gravitationacceleration . so v^2/R>g so v=sqrt(Rg)=7,14=sqrt(5,2*9,8) 3)...already answered--this do not need any number work. thedeceleration rate alway the same (regardless of mass). So If thevelocity is unchanged then the distance is unchanged

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