1)The terminal velocity of a 0.03-g drop is 5.4 m/s. Assuminga drag force F_D =

Question

1)The terminal velocity of a 0.03-g drop is 5.4 m/s. Assuminga drag force F_D = -bv, how many seconds are required for the drop,starting from rest, to reach 63 percent of terminal velocity? (Answer :
5.51 × 10-1) 2)The drag force on large objects moving through air is morenearly F_D = -bv^2. For this quadratic dependence on v, what is thevalue of the constant b (in Ns^2/m^2) if a 77-kg sky diver has aterminal velocity of 83 m/s? ( Answer:  1.10 ×10-1) 1)The terminal velocity of a 0.03-g drop is 5.4 m/s. Assuminga drag force F_D = -bv, how many seconds are required for the drop,starting from rest, to reach 63 percent of terminal velocity? (Answer :
5.51 × 10-1) 2)The drag force on large objects moving through air is morenearly F_D = -bv^2. For this quadratic dependence on v, what is thevalue of the constant b (in Ns^2/m^2) if a 77-kg sky diver has aterminal velocity of 83 m/s? ( Answer:  1.10 ×10-1)

Explanation / Answer

(1) the velocity of the object v(t)=v0*(1-exp{-b*t/m}) v0 is terminal velocity=5.4 m/s it reachs its v0 <=> mg=b*v0 =>b/m=1.82 v(t)=0.63 v0 => t=5.5*10-1 s (2) F=b*v2=mg =>b=mg/v^2=1.1* 10-1

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