You are designing a centrifuge to spin at a rate of15,850 rev/min. It takes 1 mi

Question

You are designing a centrifuge to spin at a rate of15,850 rev/min. It takes 1 min, 13 s for the centrifuge to spin up to its maximum rateof revolution from rest. Calculate the magnitude of the tangentialacceleration of the centrifuge while it is spinning up, assumingthat the tangential acceleration is constant. The tangential acceleration will be zerowhen the centrifuge reaches its maximum speed. The centripetalacceleration increases as the tangential speed of the centrifugeincreases. Use the definition of centripetal acceleration toexpress ac in terms of the speed of the testtube. Find the tangential speed of the test tube by using thedistance it travels each revolution and the time it takes tocomplete each revolution. The tangential acceleration can be foundfrom the change in the tangential speed as the centrifuge isspinning up.
m/s2 You are designing a centrifuge to spin at a rate of15,850 rev/min. It takes 1 min, 13 s for the centrifuge to spin up to its maximum rateof revolution from rest. Calculate the magnitude of the tangentialacceleration of the centrifuge while it is spinning up, assumingthat the tangential acceleration is constant. The tangential acceleration will be zerowhen the centrifuge reaches its maximum speed. The centripetalacceleration increases as the tangential speed of the centrifugeincreases. Use the definition of centripetal acceleration toexpress ac in terms of the speed of the testtube. Find the tangential speed of the test tube by using thedistance it travels each revolution and the time it takes tocomplete each revolution. The tangential acceleration can be foundfrom the change in the tangential speed as the centrifuge isspinning up.
m/s2

Explanation / Answer

= r*^2 This is the centripital acceleration. The tangential speed is equal to: v = r* so, = *v 1 revolution = 2**r meters Convert everything into seconds. Vtangential = 15850*2**r m/min = 15850*2**r/60 m/s 60 + 13 = 73 seconds to reach max speed. Assuming constant acceleration, Vtangential/time = tangential acceleration so, a = 15850*2**r/(73*60)

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