A 27.0 kg block is initially atrest on a horizontal surface. A horizontal force

Question

A 27.0 kg block is initially atrest on a horizontal surface. A horizontal force of 77.0 N is required to set the block in motion.After it is in motion, a horizontal force of 60.0 N is required to keep the block moving withconstant speed. Find the coefficients of static and kineticfriction from this information. µs = µk = A 27.0 kg block is initially atrest on a horizontal surface. A horizontal force of 77.0 N is required to set the block in motion.After it is in motion, a horizontal force of 60.0 N is required to keep the block moving withconstant speed. Find the coefficients of static and kineticfriction from this information. µs = µk =

Explanation / Answer

For static friction we have F-f=0, and F=mg, so =.291 is the static friction (using the 77N force) and F=mg or =.227 for the kinetic coefficient

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