Hello out there. Here is my question. Modern oil tankers weigh over ahalf-millio

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Hello out there. Here is my question. Modern oil tankers weigh over ahalf-million tons and have lengths of up to a quarter of a mile.Such massive ships require a distance of 5.0 km ( about 3.0 mi) anda time 19 min to come t a stop from a top speed of 34km/h. a) What is the magnitude of such a ship's average accelerationin m/s^2 in coming to a stop? ____m/s^2 b) What is the magnitude of the ship's average velocity inm/s? ____m/s A motorboat starting from rest travels in a straight line on alake. a) If the boat achieves a speed of 12 m/s in 18 s, what is theboat's average acceleration? ____m/s^2 b) Then, in 5.0 more seconds, the boat's average accelerationfor the total time? _____m/s^2 Hello out there. Here is my question. Modern oil tankers weigh over ahalf-million tons and have lengths of up to a quarter of a mile.Such massive ships require a distance of 5.0 km ( about 3.0 mi) anda time 19 min to come t a stop from a top speed of 34km/h. a) What is the magnitude of such a ship's average accelerationin m/s^2 in coming to a stop? ____m/s^2 b) What is the magnitude of the ship's average velocity inm/s? ____m/s A motorboat starting from rest travels in a straight line on alake. a) If the boat achieves a speed of 12 m/s in 18 s, what is theboat's average acceleration? ____m/s^2 b) Then, in 5.0 more seconds, the boat's average accelerationfor the total time? _____m/s^2

Explanation / Answer

1) a) the magnitude of the average acceleration is a= (change in velocity ) / time taken                                                                         =( -34 km/h ) / (19 min)                                                                        = -0.008284 m/s2 b) average velocity is = ( total distane ) / (total time)                                 = (5.0 km ) / ( 19 min)                                 =4.385 m/s 2) a) the magnitude of the average acceleration is a = (change in velocity ) / time taken                                                                         = (12 m/s ) / 18 s                                                                           =0.66m/s2

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