Two gliders approach each other on an air track. The 300-gglider is moving to th
ID: 1667397 • Letter: T
Question
Two gliders approach each other on an air track. The 300-gglider is moving to the right at 2 m/s, while the 600-g glider is moving to theleft at 4 m/s. If the velocity of the 300-g glider after the collision is 8 m/s tothe left, find the velocity of the 600-g glider after the collision, as well as itsdirection. Two gliders approach each other on an air track. The 300-gglider is moving to the right at 2 m/s, while the 600-g glider is moving to theleft at 4 m/s. If the velocity of the 300-g glider after the collision is 8 m/s tothe left, find the velocity of the 600-g glider after the collision, as well as itsdirection.Explanation / Answer
According to law of conservation of linearmomentum total linear momentum beforecollision = total linear momentumafter collision m1 *u1 + m2 *u2 = m1 *v1 + m2 *v2 mass of firstglider m1 = 300 g = 0.300 kg velocity of first glider beforecollision u1 = 2 m/s velocity of second glider aftercollision v1 = -8 m/s ( -vesign indicates motion towards left) Mass of secondglider m2 = 600 g = 0.600 kg velocity of second glider beforecollision u2 = -4 m/s ( -ve sign indicatesmotion towards left) velocity of second glider aftercollision = v2 0.300 *2 + 0.600 * (-4) = 0.300 * ( -8) + 0.600 * v2 final velocity of second glider aftercollision v2 = {0.600- 2.400 + 2.400} / 0.600 = 1.00 m/s hencesecond glider moves to the right ( + ve sign) with velocity 1.00m/s. final velocity of second glider aftercollision v2 = {0.600- 2.400 + 2.400} / 0.600 = 1.00 m/s hencesecond glider moves to the right ( + ve sign) with velocity 1.00m/s.Related Questions
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