Two gases, NO_2 and O_2, are introduced into a vessel of fixed volume at 25.0 de
ID: 487950 • Letter: T
Question
Two gases, NO_2 and O_2, are introduced into a vessel of fixed volume at 25.0 degree C; the vessel is lined with a special silver film coating the inside surface that acts as a catalyst. When an electric current is discharged into the gas mixture, a reaction occurs according to the equation below. As you can see, the stoichiometric coefficients are missing (but you will find them). The vessel is allowed to reattain 25.0 degree C before the final partial pressure readings are made: __ NO_2 (g) + ___ O_2 (g) rightarrow __ N_2O (g) + ___ O_3 (g) P_initial 0.80 atm 1.40 atm 0.00 atm 0.00 atm change during rxn P_final 0.00 atm 0.80 atm ___atm ___atm Please complete the line above entitled "change during rxn" (rxn is the standard abbreviation for reaction). Please write the coefficients into the equation above (use the lowest integer ratio, please) Please fill in the two blanks on the P_final line The limiting reactant is ________ The mole fraction (one integer divided by another) of O_2 before reaction is ________ The mole fraction (one integer divided by another) of O_2 after reaction is _________ The two gas parameters that are constant during this process are ________ If you painted clouds on the outside of the reaction vessel while you were doing this experiment, you could validate a commonly used term applied to the "surprising result often found when addressing a difficult situation" (please write your answer below):Explanation / Answer
For the given reaction,
2NO2(g) + O2(g) ---> N2O(g) + 2O3(g)
Pinitial 0.8 atm 1.4 atm - -
C -0.8 -0.4 +0.4 +0.8
Pfinal 0.00 1.0 0.4 0.8
The limiting reactant is NO2
The mole fraction of O2 = 1.4/(1.4 + 0.8) = 0.636
The mole fraction of O2 after the reaction = 1.0/(1.0 + 0.4 + 0.8) = 0.833
The two gas parameters that are constant during the process are, Temperature and volume
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