a proton is realeased at rest from the positive platecapacitor with a vacuum bet

Question

a proton is realeased at rest from the positive platecapacitor with a vacuum between its plates. if the electric fieldb/w the plates is 200,000 V/M and plates are 2.00 mm apart (a) whatis the kinetic energy of the proton as it reaches the negativeplate and (b) the initial acceleration of the proton. im stuck! a proton is realeased at rest from the positive platecapacitor with a vacuum between its plates. if the electric fieldb/w the plates is 200,000 V/M and plates are 2.00 mm apart (a) whatis the kinetic energy of the proton as it reaches the negativeplate and (b) the initial acceleration of the proton. im stuck!

Explanation / Answer

Mass of proton m = 1.67 * 10 ^ -27 kg

Charge of proton q = 1.6 * 10^-19 C

Electric field E = 200000 V / m

Separation d= 2 mm = 2 * 10 ^ -3 m

Accleartion a = Eq / m

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