A rocket of mass 4.50 x 10 5 kg is in flight. Its thrust is directed at an angle

Question

A rocket of mass 4.50 x 105 kg is in flight. Its thrust is directed at an angle of 51.5 degrees above thehorizontal and has a magnitude of 8.70 x 106 N. Find the magnitude and direction of the rockets acceleration. Givethe direction as an angle above the horizontal. I found that the magnitude is 12.04 m/s2. How do Ifind the direction as an angle above the horizontal? Thanks. A rocket of mass 4.50 x 105 kg is in flight. Its thrust is directed at an angle of 51.5 degrees above thehorizontal and has a magnitude of 8.70 x 106 N. Find the magnitude and direction of the rockets acceleration. Givethe direction as an angle above the horizontal. I found that the magnitude is 12.04 m/s2. How do Ifind the direction as an angle above the horizontal? Thanks.

Explanation / Answer

sinceF=ma    Newton's law, it is vector, so acceleration a has the same direction ofF, so it is  51.5 degrees above thehorizontal |a| = |F|/m =  8.70 x 106 N / 4.50 x105 kg = 19.33 m/s2 answer: magnitude: 19.33m/s2 direction: 51.5 degrees above the horizontal direction: 51.5 degrees above the horizontal

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