At amusement parks, there is a popular ride where the floor of arotating cylindr

Question

At amusement parks, there is a popular ride where the floor of arotating cylindrical room falls away, leaving the backs of theriders "plastered" against the wall. Suppose the radius of the roomis 3.45 m and the speed of the wall is10.6 m/s when the floor falls away. (a) What is the source of the centripetal forceacting on the riders? 1 the normal force exerted on the rider bythe wall the cavitron force between the rider andthe wall     the gravitationalforce the strong force between the rider andthe wall

(b) How much centripetal force acts on a 55.0 kg rider?
2 N

(c) What is the minimum coefficient of static friction that mustexist between the rider's back and the wall, if the rider is toremain in place when the floor drops away?
3 (a) What is the source of the centripetal forceacting on the riders? 1 the normal force exerted on the rider bythe wall the cavitron force between the rider andthe wall     the gravitationalforce the strong force between the rider andthe wall

(b) How much centripetal force acts on a 55.0 kg rider?
2 N

(c) What is the minimum coefficient of static friction that mustexist between the rider's back and the wall, if the rider is toremain in place when the floor drops away?
3 1 the normal force exerted on the rider bythe wall the cavitron force between the rider andthe wall     the gravitationalforce the strong force between the rider andthe wall 1 the normal force exerted on the rider bythe wall the cavitron force between the rider andthe wall     the gravitationalforce the strong force between the rider andthe wall 1

Explanation / Answer

(a) correct answer is: the normal force exerted on therider by the wall (b) magnitude of centripetal force by using 2nd Newton's Law F=m.v2/r=1791.2 N (c) we have static*F=m*g =>static=0.3

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