Three charges are on a line (look below),The charges are q1=-4.5 microcoloumbs,

Question

   Three charges are on a line (look below),The charges are q1=-4.5 microcoloumbs, q2=3.0 microcoloumbs,q3=-2.5microcoloumbs. A. what is the direction of the net force on charge q1? B. what is the magnitude of the net force on charge q2? C. what are the magnitude and direction of the electric fieldexperienced by q1? q2..........q1..........q3      0.20m    0.15m    Three charges are on a line (look below),The charges are q1=-4.5 microcoloumbs, q2=3.0 microcoloumbs,q3=-2.5microcoloumbs. A. what is the direction of the net force on charge q1? B. what is the magnitude of the net force on charge q2? C. what are the magnitude and direction of the electric fieldexperienced by q1? q2..........q1..........q3      0.20m    0.15m

Explanation / Answer

F = -q1*q2*k/r^2

E = -qk/r^2
So, because it's in one dimension:

Fx = -q1q2k/x^2    Be sure to account for direction (i.e. if the charge is tothe left of the point in question, you multiply by an additionalnegative value to represent the direction vector beingnegative.)

So, for example for the x component Fx on q3 we have:

Fx = -q3*k( -(q1)/.35^2 + -(q2)/.15^2):       Notice that because both chargesare to the left of the charge in question, there's an extranegative factor multiplied on to both due to the fact that they'reto the left of charge q3.. By this method, a positive forcewill be in the positive x direction. a negative force will e in thenegative x direction.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.